Code can always find the current line number in the special symbol __LINE__
, the current file in __FILE__
, and the current package in __PACKAGE__
. But there's no such symbol for the current subroutine name, let alone the name of the one that called this subroutine.
The built-in function caller
handles all of these. In scalar context it returns the calling function's package name. But in list context, it returns a wealth of information. You can also pass it a number indicating how many frames (nested subroutine calls) back you'd like information about: 0 is your own function, 1 is your caller, and so on.
Here's the full syntax, where $i
is how far back you're interested in:
($package, $filename, $line, $subr, $has_args, $wantarray )= caller($i);
# 0 1 2 3 4 5
Here's what each of those return values means:
$package
The package that the code was compiled in.
$filename
The name of the file the code was compiled in, reporting -e
if launched from the command-line switch of the same name, or -
if the script was read from STDIN.
$line
The line number that frame was called from.
$subr
The name of that frame's function, including its package. Closures return names like main::__ANON__
, which are not callable. In eval
it returns "(eval)"
.
$has_args
Whether the function was called with arguments.
$wantarray
The value the wantarray
function would return for that stack frame; either true, false but defined, or else undefined (respectively). This tells you whether the function was called in list, scalar, or void context.
Rather than using caller
directly as in the solution, you might want to write functions instead:
$me = whoami();
$him = whowasi();
sub whoami { (caller(1))[3] }
sub whowasi { (caller(2))[3] }
These use arguments 1 and 2 for parent and grandparent functions because the call to whoami
or whowasi
would be number 0.